If you happened to know that the elements are given in the correct order, you could maintain a pointer to the tail of the list, and keep inserting there, which would take $O(n)$. Sorting ahead means all n elements are known before any need to be inserted. Quora - A place to share knowledge and better keep moving until you reach a node who's value is greater than Information on this topic is now available on Wikipedia at: Search data structure. It really is a tricky question. 2) If the value of the node to be inserted is smaller than the value of the head node, then insert the node at the There are also algorithms which are non-comparative such as Radix sort which their complexity depends on the size in bits which the numbers need to be stored in memory. This is the case if you have a constant number $A$ of pointers (you implicitly assumed $A=1$, with a single pointer at the start of the list), so that you need to traverse at least $k/A$ nodes after $k$ insertions in the worst case. I guess I will start you off with the time complexity of a linked list: The proposed solution first does some preprocessing of the arguments to insert, then does the insertion proper. This question is more about reading comprehension than about algorithms. Note that there is a constant factor for the hashing algorithm, the input node. The Time complexity of insertion sort depends on the number of inversions in the input array. In a given array, if (i < j) and (A [i] > A [j]) then the pair (i, j) is called an inversion of an array A, note that i and j are the array indexes. sorting - Time complexity of insertion in linked list - Computer Assume the array has unused slots and the elements are packed from the Asking for help, clarification, or responding to other answers. (In such a scenario, you'd need to ensure that inserting one element is atomic.) I suppose the second approach you propose implies the use of a secondary data structure like a dynamic array. It should be O(n). By clicking Post Your Answer, you agree to our terms of service, privacy policy and cookie policy. Note that even under this assumption, your reasoning is wrong, or at least imprecise. What is this brick with a round back and a stud on the side used for? The way it's worded, it's a bit of a trick question.
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